A) \[9{{x}^{2}}-12y=8\]
B) \[4{{x}^{2}}-3y=2\]
C) \[{{x}^{2}}-3y=2\]
D) \[9{{x}^{2}}-3y=2\]
Correct Answer: A
Solution :
Let \[P\equiv (2t,{{t}^{2}})\] Given |
By section formula \[\frac{(0)(2)+2t(1)}{3}=h\] (i) and |
\[\frac{(-1)(2)+{{t}^{2}}(1)}{3}=k\] (ii) by (i) and (ii) |
\[\Rightarrow 3k+2={{\left( \frac{3h}{2} \right)}^{2}}\] |
\[\Rightarrow 12y+8=9{{x}^{2}}\] |
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