JEE Main & Advanced JEE Main Paper Phase-I (Held on 09-1-2020 Evening)

  • question_answer
    Two steel wires having same length are suspended from a ceiling under the same load. If the ratio of their energy stored per unit volume is 1 : 4, the ratio of their diameters is [JEE MAIN Held on 09-01-2020 Evening]

    A) \[\sqrt{2}:1\]

    B) \[2:1\]

    C) \[1:\sqrt{2}\]

    D) \[1:2\]

    Correct Answer: A

    Solution :

    Energy density \[=\frac{1}{2}\,stress\times strain\] Energy density\[=\frac{1}{2}\frac{F}{A}\times \frac{F}{AY}\] \[\frac{{{u}_{1}}}{{{u}_{2}}}={{\left( \frac{{{d}_{2}}}{d{{}_{1}}} \right)}^{4}}\] \[\frac{{{d}_{1}}}{{{d}_{2}}}={{\left( 4 \right)}^{1/4}}\] \[\frac{{{d}_{1}}}{{{d}_{2}}}=\sqrt{2}:1\]


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