JEE Main & Advanced JEE Main Paper Phase-I (Held on 09-1-2020 Evening)

  • question_answer
      Two identical capacitors A and B, charged to the same potential 5V are connected in two different circuits as shown below at time t = 0. If the charge on capacitors A and B at time t = CR is \[{{Q}_{A}}\] and \[{{Q}_{B}}\] respectively, then (Here e is the base of natural logarithm)    [JEE MAIN Held on 09-01-2020 Evening]

    A) \[{{Q}_{A}}=\frac{CV}{2},{{Q}_{B}}=\frac{VC}{e}\]

    B) \[{{Q}_{A}}=VC,{{Q}_{B}}=CV\]

    C) \[{{Q}_{A}}=\frac{CV}{e},{{Q}_{B}}=\frac{VC}{2}\]

    D) \[{{Q}_{A}}=VC,{{Q}_{B}}=\frac{VC}{e}\]

    Correct Answer: D

    Solution :

    In case I diode is reverse biased \[{{Q}_{A}}\text{ }=\text{ }CV\] n case II, current will flow as diode is forward biased. \[{{Q}_{B}}=\frac{CV}{e}\]


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