JEE Main & Advanced JEE Main Paper Phase-I (Held on 09-1-2020 Morning)

  • question_answer
    A chemist has 4 samples of artificial sweetener A, B, C and D. To identify these samples, he performed certain experiments and noted the following observations :
    (i) A and D both form blue-violet colour with ninhydrin.
    (ii) Lassaigne extract of C gives positive \[AgN{{O}_{3}}\]  test and negative \[F{{e}_{4}}{{\left[ Fe{{\left( CN \right)}_{6}} \right]}_{3}}\]test.
    (iii) Lassaigne extract of B and D gives positive sodium nitroprusside test.
    Based on these observations which option is correct?
    [JEE MAIN Held on 09-01-2020 Morning]

    A)
    A : Aspartame; B : Alitame;
    C : Saccharin; D : Sucralose

    B)
    A : Saccharin; B : Alitame;
    C : Sucralose; D : Aspartame

    C)
    A : Alitame; B : Saccharin;
    C : Aspartame; D : Sucralose

    D)
    A : Aspartame; B : Saccharin;
    C : Sucralose; D : Alitame

    Correct Answer: D

    Solution :

    [d]  Ninhydrin test is specific for amino acids. Both aspartame and alitame contains amino acids. Alitame is sulphur containing compound thats why gives sodium nitroprusside test Saccharin also contains sulphur Sucralose contains chloro group thats why its Lassaigne extract gives white ppt with\[AgN{{O}_{3}}\]. \[\therefore \] A = Aspartame,      B = Saccharin C = Sucralose,   D = Alitame.


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