Initial concentration (A) | Initial Concentration (B) | Initial rate of formation of C \[(mol\,{{L}^{-}}{{S}^{-}})\] |
\[0.1M\] | \[0.1M\] | \[1.2\times {{10}^{-3}}\] |
\[0.1M\] | \[0.2M\] | \[1.2\times {{10}^{-3}}\] |
\[0.2M\] | \[0.1M\] | \[2.4\times {{10}^{-3}}\] |
A) \[\frac{dc}{dt}=k[A]{{[B]}^{2}}\]
B) \[\frac{dc}{dt}=k[A]\]
C) \[\frac{dc}{dt}=k[A][B]\]
D) \[\frac{dc}{dt}=k{{[A]}^{2}}[B]\]
Correct Answer: B
Solution :
\[r=k{{[A]}^{x}}{{[B]}^{y}}\] \[1.2\times {{10}^{-3}}=k{{(0.1)}^{x}}{{[0.1]}^{y}}\] ??.. (I) \[1.2\times {{10}^{-3}}=k{{(0.1)}^{x}}{{[0.2]}^{y}}\] ??.. (II) From (I) and (II)\[\left( \frac{1}{2} \right)={{\left( \frac{1}{2} \right)}^{x}}\Rightarrow x=1\]??.. (III) Hence\[\frac{dc}{dt}=k(A)'\]You need to login to perform this action.
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