A) 1%
B) 5%
C) 2%
D) 3%
Correct Answer: D
Solution :
\[T=2\pi \sqrt{\frac{L}{g}}\] \[\frac{t}{n}=2\pi \sqrt{\frac{L}{g}}\] \[\frac{{{t}^{2}}}{{{n}^{2}}}=4{{\pi }^{2}}\frac{L}{g}\] \[g=\frac{4\pi {{L}^{2}}{{n}^{2}}}{{{t}^{2}}}\] \[\ln g=\ln 4\pi {{n}^{2}}+2\ln L-2\ln t\] \[\frac{dg}{g}=\frac{2\pi L}{L}-2\frac{dt}{t}\] \[\frac{dg}{g}\times 100=2\times \frac{0.1}{20}\times 100+2\frac{1}{90}\times 100=1+\frac{20}{9}\simeq 3%\]
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