A) \[92\pm 3\text{ }s\]
B) \[92\pm 2s\]
C) \[92\pm 5.0s\]
D) \[92\pm 1.8\text{ }s\]
Correct Answer: B
Solution :
Ans. (2) Sol. \[{{T}_{AV}}=92s\] \[{{(|\Delta T|)}_{mean}}=1.5s\]since uncertainity is 1.5 s so digit 2 in 92 is uncertain. so reported mean time should be \[92\pm 2\] Ref : NCERT (XIth) Ex. 2.7, Page. 25
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