A) \[\text{1}.\text{34}\times \text{1}{{0}^{\text{2}}}\text{mol mi}{{\text{n}}^{\text{1}}}\]
B) \[\text{6}.\text{93}\times \text{1}{{0}^{\text{2}}}\text{mol mi}{{\text{n}}^{\text{1}}}\]
C) \[\text{6}.\text{93}\times \text{1}{{0}^{\text{4}}}\text{mol mi}{{\text{n}}^{\text{1}}}\]
D) \[\text{2}.\text{66 Lmi}{{\text{n}}^{\text{1}}}\text{at STP}\]
Correct Answer: C
Solution :
\[{{H}_{2}}{{O}_{2(aq)}}\xrightarrow[{}]{{}}{{H}_{2}}{{O}_{(aq)}}+\frac{1}{2}{{O}_{2}}(g)\] \[k=\frac{1}{t}\ln \left( \frac{{{a}_{0}}}{{{a}_{t}}} \right)\] \[=\frac{1}{50}\ln \left( \frac{0.5}{0.125} \right)\] \[=\frac{1}{50}\ell \ln 4{{\min }^{-1}}\] \[\frac{\text{Rate of disappearance of }{{\text{H}}_{\text{2}}}{{O}_{2}}}{1}\] \[=\frac{\text{Rate of appearance of }{{O}_{2}}}{\frac{1}{2}}\] \[(Rate){{O}_{2}}=\frac{1}{2}\times (Rate){{H}_{2}}{{O}_{2}}\] \[=\frac{1}{2}k[{{H}_{2}}{{O}_{2}}]\] \[=\frac{1}{2}\times \frac{1}{50}\times \ell n4\times 0.05\] \[=\text{6}.\text{93}\times \text{1}{{0}^{\text{4}}}\text{M mi}{{\text{n}}^{\text{1}}}\]
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