2. Solved Papers
  3. JEE Main & Advanced

JEE Main & Advanced JEE Main Solved Paper-2017

  • question_answer
    Some energy levels of a molecule are shown in the figure. The ratio of the wavelengths \[r={{\lambda }_{1}}/{{\lambda }_{2}},\]is given by:          JEE Main Solved Paper-2017

    A)  \[r=\frac{3}{4}\]                             

    B)  \[r=\frac{1}{3}\]

    C)  \[r=\frac{4}{3}\]                             

    D)  \[r=\frac{2}{3}\]

    Correct Answer: B

    Solution :

     \[\Delta E=\frac{hC}{\lambda }\] For         \[{{\lambda }_{1}}\]\[-E-(-2E)=\frac{hC}{{{\lambda }_{1}}}\]                                 \[{{\lambda }_{1}}=\frac{hC}{E}\]                 For\[{{\lambda }_{2}}\] \[-E-\left( -\frac{4E}{3} \right)=\frac{hC}{{{\lambda }_{2}}}\] \[{{\lambda }_{2}}=\frac{3hC}{E}\] \[\frac{{{\lambda }_{1}}}{{{\lambda }_{2}}}=r=\frac{1}{3}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner