A) 9.75 mm
B) 15.6 mm
C) 1.56 mm
D) 7.8 mm
Correct Answer: D
Solution :
For common maxima \[{{n}_{1}}{{\lambda }_{1}}={{n}_{2}}{{\lambda }_{2}}\] \[{{n}_{1}}\times 650={{n}_{2}}\times 520\] \[\frac{{{n}_{1}}}{{{n}_{2}}}=\frac{4}{5}\] \[\frac{yd}{D}=n\lambda \] \[y=\frac{4\times 650\times {{10}^{-9}}\times 1.5}{0.5\times {{10}^{-3}}}\] \[y=7.8\,mm\]
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