JEE Main & Advanced JEE Main Solved Paper-2017

  • question_answer
    If S is the set of distinct values of 'b' for which the following system of linear equations \[x+y+z=1\] \[x+ay+z=1\] \[ax+by+z=0\] has no solution, then S is :       JEE Main Solved Paper-2017

    A)  a singleton

    B)  an empty set

    C)  an infinite set

    D)  a finite set containing two or more elements

    Correct Answer: A

    Solution :

     \[D=\left| \begin{matrix}    1 & 1 & 1  \\    1 & a & 1  \\    a & b & 1  \\ \end{matrix} \right|=0\Rightarrow a=1\] and at \[a=1\] \[{{D}_{1}}={{D}_{2}}={{D}_{3}}=0\] \[\begin{matrix}    \text{First}\,\text{two}\,\text{equations}\,\text{are}  \\    \text{and}\,\text{third}\,\text{equation}\,\text{is}  \\ \end{matrix}\left. \begin{matrix}    x+y+z=1  \\    x+y+z=0  \\ \end{matrix} \right]\Rightarrow \text{There}\,\text{is}\,\text{no}\,\text{solution}\] \[\therefore \]  \[b=\{1\}\Rightarrow \]it is a singleton set


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