A) \[\frac{3\alpha }{PK}\]
B) \[3PK\alpha \]
C) \[\frac{P}{3\alpha K}\]
D) \[\frac{P}{\alpha K}\]
Correct Answer: C
Solution :
Due to thermal expansion \[\frac{\Delta v}{v}=3\alpha \Delta T\] Due to External pressure \[\frac{\Delta v}{v}=\frac{P}{K}\] Equating both \[{{w}_{1}}\]get \[3\alpha \Delta T=\frac{P}{K}\] \[\Delta T=\frac{P}{3\alpha K}\]You need to login to perform this action.
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