A) 17.3 GHz
B) 15.3 GHz
C) 10.1 GHz
D) 12.1 GHz
Correct Answer: A
Solution :
Doppler effect in light (speed of observer is not very small compare to speed of light) \[{{f}^{1}}=\sqrt{\frac{1+V/C}{1-V/C}}{{f}_{source}}=\sqrt{\frac{1+1/2}{1-1/2}}(10\,GHz)\] \[=17.3\,GHz\]You need to login to perform this action.
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