A) 2a
B) \[2\sqrt{2}a\]
C) \[\sqrt{2}a\]
D) \[\frac{a}{\sqrt{2}}\]
Correct Answer: D
Solution :
In FCC unit cell atoms are in contant along face diagonal So, \[\sqrt{2}a=4R\] \[\therefore \] closest distance \[(2R)=\frac{\sqrt{2}a}{2}=\frac{a}{\sqrt{2}}\]You need to login to perform this action.
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