A) 8
B) 12
C) 6
D) 4
Correct Answer: D
Solution :
From arrhenius equation, \[K=A.{{e}^{\frac{-Ea}{RT}}}\] So, \[{{K}_{1}}=A.{{e}^{-{{E}_{{{a}_{1}}}}/RT}}\] ?.. \[{{K}_{2}}=A.{{e}^{-{{E}_{{{a}_{2}}}}/RT}}\] ?.. So, equation \[(2)(1)\Rightarrow \frac{{{K}_{2}}}{{{K}_{1}}}={{e}^{\frac{({{E}_{{{a}_{1}}}}-{{E}_{{{a}_{2}}}})}{RT}}}\] (As pre-exponential factors of both reactions is same) \[\ln \left( \frac{{{K}_{2}}}{{{K}_{1}}} \right)=\frac{{{E}_{{{a}_{1}}}}-{{E}_{{{a}_{2}}}}}{RT}=\frac{10,000}{8.314\times 3000}=4\]You need to login to perform this action.
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