A) \[+\,74.8\,kJ\,mo{{l}^{-1}}\]
B) \[+\,144.0\,\,kJ\,mo{{l}^{-1}}\]
C) \[-74.8\,\,kJ\,mo{{l}^{-1}}\]
D) \[-144.0\,kJ\,mo{{l}^{-1}}\]
Correct Answer: C
Solution :
\[C{{O}_{2}}(g)+2{{H}_{2}}O(\ell )\to C{{H}_{4}}(g)+2{{O}_{2}}(g);{{\Delta }_{r}}{{H}^{o}}=890.3\] \[{{\Delta }_{f}}{{H}^{o}}-393.5-285.8\,\,\,\,?\,\,\,\,\,\,0\] \[{{\Delta }_{r}}{{H}^{o}}={{\sum{({{\Delta }_{f}}{{H}^{o}})}}_{\text{product}}}-{{\sum{({{\Delta }_{f}}{{H}^{o}})}}_{\text{reactan}\,\text{ts}}}\]\[890.3=\left[ 1\times {{({{\Delta }_{f}}{{H}^{o}})}_{C{{H}_{4}}}}+2\times 0 \right]-[1\times (-393.5)+2(-285.8)]\]\[{{({{\Delta }_{f}}{{H}^{o}})}_{C{{H}_{4}}}}=890.3-965.1=-74.8\,kJ/mol\]You need to login to perform this action.
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