JEE Main & Advanced Physics Alternating Current / प्रत्यावर्ती धारा JEE PYQ-Alternating Current

  • question_answer
    In LC circuit the inductance \[L=40\,mH\] and capacitance \[C=100\,\mu F.\] If a voltage \[V(t)=10\,\sin (314\,\,t)\] is applied to the circuit, the current in the circuit is given as [JEE MAIN Held on 09-01-2020 Evening]

    A) \[0.52\,\,\sin \,\,314\,\,t\]

    B) \[5.2\,\cos \,\,314\,t\]

    C) \[10\,\cos \,\,314\,t\]

    D) \[0.52\,\,\cos \,\,314\,t\]

    Correct Answer: D

    Solution :

    [d]   \[Z={{x}_{C}}-{{x}_{L}}\]
                \[Z=\frac{1}{\omega C}-\omega L\]
                \[=\frac{1}{314\times 100\times {{10}^{-6}}}-314\times 40\times {{10}^{-3}}\]
                \[=19.28\,\Omega \]
                \[i=\frac{{{V}_{0}}}{Z}\,\,\sin \,\,(\omega t+\pi /2)\]


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