A) 750 W
B) 500 W
C) 250W
D) 1000 W
Correct Answer: C
Solution :
| [c] As resistance \[R=\frac{{{V}^{2}}}{P}=\frac{{{(200)}^{2}}}{1000}\] |
| where, V and P are denoting rated voltage and power, respectively. |
| \[\therefore \] \[{{P}_{consumed}}=\frac{{{V}^{2}}_{applied}}{R}\] |
| \[=\frac{110\times 110}{220\times 220}\times 1000\] |
| = 250 W |
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