A) \[10\text{ k}\,\Omega \]
B) \[9.9\text{ }k\Omega \]
C) \[8.9\text{ }k\Omega \]
D) \[7.9\text{ }k\Omega \]
Correct Answer: B
Solution :
| [b] V = 10 volt |
| When 1 mA current will be flowing |
| \[\therefore 10=1\times {{10}^{3\text{ }}}\left( 100+{{R}_{0}} \right)\] |
| \[\Rightarrow 10000100=9900\text{ }\Omega ={{R}_{0}}\] |
| \[\Rightarrow {{R}_{0}}=9.9\text{ }k\Omega \] |
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