A) \[19.8\times {{10}^{-7}}kg\]
B) \[9.9\times {{10}^{-7}}kg\]
C) \[6.6\times {{10}^{-7}}kg\]
D) \[1.1\times {{10}^{-7}}kg\]
Correct Answer: A
Solution :
| [a] Mass of substance liberated at cathode |
| \[m=zit\] |
| where,\[z=\]electrochemical equivalent |
| \[=3.3\times {{10}^{-7}}kg/C\] |
| \[i=\]current flowing\[=3A,\] |
| \[t=2s\] |
| \[\therefore \] \[m=3.3\times {{10}^{-7}}\times 3\times 2=19.8\times {{10}^{-7}}kg\] |
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