A) 75 W
B) 40 W
C) 25 W
D) 50 W
Correct Answer: C
Solution :
| [c] Resistance of electric bulb, \[R=\frac{{{V}^{2}}}{P}\] |
| Where subscripts denote for rated parameters. |
| \[R=\frac{{{(220)}^{2}}}{100}\] |
| Power consumed at 110 V, \[{{P}_{consumed}}=\frac{{{V}^{2}}}{R}\] |
| \[\therefore \] \[{{P}_{consumed}}=\frac{{{(110)}^{2}}}{{{(220)}^{2}}/100}=25W\] |
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