JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर JEE PYQ-Current Electricity Charging and Discharging of Capacitors

  • question_answer
    Two electric bulbs marked 25W- 220V and 100W - 220 V are connected in series to a 440 V supply. Which of the bulbs will fuse?            [AIEEE 2012]

    A) both     

    B) 100W

    C) 25W

    D) neither 

    Correct Answer: C

    Solution :

    [c]        
                 
    As \[{{R}_{1}}=\frac{220}{25}\times 200\] and \[{{R}_{2}}=\frac{220}{100}\times 220\]
    \[R={{R}_{1}}+{{R}_{2}}\]
    \[=220\times 220\left( \frac{1}{25}+\frac{1}{100} \right)\]
    \[=220\times 220\frac{1}{20}\]
    \[\therefore \,{{I}_{live}}=\frac{440}{\frac{220\times 220}{20}}=\frac{40}{220}A\]
    \[\therefore \] 1st bulb (25 W) will fuse only


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