| A 6.0 volt battery is connected to two light bulbs as shown in figure. Light bulb 1 has resistance 3 ohm while light bulb 2 has resistance 6 ohm. |
| Battery has negligible internal resistance. Which bulb will glow brighter? [JEE ONLINE 19-05-2012] |
 |
A) Bulb 1 will glow more first and then its brightness will become less than bulb 2
B) Bulb 1
C) Bulb 2
D) Both glow equally
Correct Answer: B
Solution :
| [b] Total resistance \[=\frac{6\times 3}{6+3}=2\Omega \] |
| Current in circuit \[=\frac{6}{2}=3A\] |
| Therefore current through bulb 1 is 2A and bulb 2 is 1A So bulb 1 will glow more |
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