JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर JEE PYQ-Current Electricity Charging and Discharging of Capacitors

  • question_answer
    Four bulbs B1, B2, B3 and B4 of 100 W each are connected to 220 V main as shown in the figure. [JEE ONLINE 19-04-2014]
    The reading in an ideal ammeter will be:

    A) 0.45 A

    B) 0.90 A

    C) 1.35 A

    D) 1.80 A

    Correct Answer: C

    Solution :

    [c] Current in each bulb \[=\frac{\text{Power}}{\text{Voltage}}\]
    \[=\frac{100}{220}=0.45A\]
    Current through ammeter \[=0.45\times 3=1.35A\]


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