JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर JEE PYQ-Current Electricity Charging and Discharging of Capacitors

  • question_answer
    To know the resistance G of a galvanometer by half deflection method, a battery of emf \[{{V}_{E}}\] and resistance R is used to deflect the galvanometer by angle\[\theta .\]If a shunt of resistance S is needed to gat half deflection then G, R and S are related by the equation:   [JEE ONLINE 09-04-2016]

    A) 2S = G

    B) 2G = S

    C) S(R+G) = RG

    D) 2S(R+G) = RG

    Correct Answer: C

    Solution :

    [c] Case-1                                 
    Case-2
    \[{{i}_{1}}=\frac{{{V}_{E}}}{R+G}\]             
    \[i=\frac{{{V}_{E}}}{R+\frac{GS}{G+S}}\]
    \[\frac{{{i}_{1}}}{2}G=\left( i-\frac{{{i}_{1}}}{2} \right)S\]                       
    \[{{i}_{1}}(G+S)=2iS\]
    substituting \[{{i}_{1}}\] and i we get S(R+G) = RG


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