JEE Main & Advanced Physics Elasticity JEE PYQ-Elasticity

  • question_answer
    A uniform cylindrical rod of length L and radius r, is made from a material whose Young's modulus of Elasticity equals Y. When this rod is heated by temperature T and simultaneously subjected to a net longitudinal compressional force F, its length remains unchanged. The coefficient of volume expansion, of the material of the rod, is (nearly) equals to : [JEE Main 12-4-2019 Afternoon]

    A) \[F/(3\pi {{r}^{2}}YT)\]

    B)      \[3F/(\pi {{r}^{2}}YT)\]

    C) \[6F/(\pi {{r}^{2}}YT)\]

    D)      \[9F/(\pi {{r}^{2}}YT)\]

    Correct Answer: B

    Solution :

    [b]
               
    \[\therefore \] Length of cylinder remains unchanged
    so\[{{\left( \frac{F}{A} \right)}_{Compressive}}={{\left( \frac{F}{A} \right)}_{Thermal}}\]
    \[\frac{F}{\pi {{r}^{2}}}=Y\alpha T\]
    (\[\alpha \]is linear coefficient of expansion)
    \[\therefore \]\[\alpha =\frac{F}{YT\pi {{r}^{2}}}\]
    \[\therefore \]The coefficient of volume expansion\[\gamma =3\alpha \]
    \[\therefore \]\[\gamma =3\frac{F}{YT\pi {{r}^{2}}}\]


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