JEE Main & Advanced Physics Electro Magnetic Induction JEE PYQ-Electro Magnetic Induction

  • question_answer
    A metal conductor of length 1m rotates vertically about one of its ends at angular velocity 5 rad/s. If the horizontal component of the earth's magnetic field is\[0.2\times {{10}^{-4}}T\]then the emf developed between the two ends of the conductor is                       [AIEEE 2004]

    A) \[5\mu V\]

    B) \[50\mu V\]

    C) \[5mV\]

    D) \[50\,mV\]

    Correct Answer: B

    Solution :

    [b] The emf induced between ends of conductor,
    \[e=\frac{1}{2}B\omega {{L}^{2}}\]
    \[=\frac{1}{2}\times 0.2\times {{10}^{-4}}\times 5\times {{(1)}^{2}}\]
    \[=0.5\times {{10}^{-4}}V\]
    \[=5\times {{10}^{-5}}V\]
    \[=50\mu V\]


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