JEE Main & Advanced Physics Electro Magnetic Induction JEE PYQ-Electro Magnetic Induction

  • question_answer
    A generator has armature resistance of \[0.1\Omega \]and develops an induced emf of 120 F when driven at its rated speed. Its terminal voltage when a current of 50 A is being drawn is [JEE ONLINE 19-05-2012]

    A) 120 V

    B) 5V

    C) 115 V

    D) 70 V

    Correct Answer: C

    Solution :

    [c] Armature resistance \[R=0.1\Omega \]
    Induced emf, e = 120V
    Current drown, I = 50 A
    We know that,
    e = V + IR or, V= e - IR = 120 - 50 \[\times \] 0.1 = 115V


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