JEE Main & Advanced Physics Fluid Mechanics, Surface Tension & Viscosity / द्रव यांत्रिकी, भूतल तनाव और चिपचिपापन JEE PYQ-Fluid Mechanics, Surface Tension and Viscosity

  • question_answer
    If surface tension (S), Moment of inertia (I) and Planck's constant (h), were to be taken as the fundamental units, the dimensional formula for linear momentum would be :-               [JEE Main 8-4-2019 Afternoon]

    A) \[{{S}^{3/2}}{{I}^{1/2}}{{h}^{0}}\]          

    B)      \[{{S}^{1/2}}{{I}^{1/2}}{{h}^{0}}\]

    C) \[{{S}^{1/2}}{{I}^{1/2}}{{h}^{-1}}\]         

    D)      \[{{S}^{1/2}}{{I}^{3/2}}{{h}^{-1}}\]

    Correct Answer: B

    Solution :

    [b] \[p=k\,{{s}^{s}}{{I}^{b}}{{h}^{c}}\]
    where k is dimensionless constant
    \[ML{{T}^{-1}}={{(M{{T}^{-2}})}^{a}}{{(M{{L}^{2}})}^{b}}{{(M{{L}^{2}}{{T}^{-1}})}^{c}}\]
    \[a+b+c=1\]
    \[2b+2c=1\]
    \[2ac=1\]
    \[a=\frac{1}{2}\,\,\,\,\,\,\,\,\,\,\,b=\frac{1}{2}\,\,\,\,\,\,\,\,\,\,\,\,\,c=0\]
    \[{{s}^{1/2}}{{I}^{1/2}}{{h}^{0}}\]


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