A) \[4M\]
B) \[M\]
C) \[2M\]
D) \[\frac{M}{2}\]
Correct Answer: C
Solution :
| [c] Height of liquid rise in capillary tube \[h=\frac{2T\cos {{\theta }_{C}}}{\rho rg}\]\[\Rightarrow h\propto \frac{1}{r}\] |
| when radius becomes double height become half |
| \[\therefore \]\[h'=\frac{h}{2}\] |
| Now,\[M=\pi {{r}^{2}}h\times \rho \]and \[M'=\pi {{(2r)}^{2}}(h/2)\times \rho =2M\] |
| Option [c] |
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