question_answer

The height at which the acceleration due to gravity becomes\[\frac{g}{9}\](where g = the acceleration due to gravity on the surface of the earth) in terms of R, the radius of the earth, is:                                                [AIEEE 2009]

A)  2R

B)       \[\frac{R}{\sqrt{2}}\]

C)  R/2                 

D)      \[\sqrt{2}R\]

Correct Answer: A

Solution :

[a]