question_answer

Two particles of equal mass 'm' go around a circle of radius R under the action of their mutual gravitational attraction. The speed of each partial with respect to their centre of mass is:           [AIEEE 11-05-2011]

A) \[\sqrt{\frac{Gm}{4R}}\]

B)                  \[\sqrt{\frac{Gm}{3R}}\]

C) \[\sqrt{\frac{Gm}{2R}}\]

D)      \[\sqrt{\frac{Gm}{R}}\]

Correct Answer: A

Solution :

[a]