question_answer

Four particles, each of mass M and equidistant from each other, move along a circle of radius R under the action of their mutual gravitational attraction. The speed of each particle is:                                              [JEE MAIN 2014]

A)  \[\sqrt{\frac{GM}{R}\left( 1+2\sqrt{2} \right)}\]  

B)  \[\frac{1}{2}\sqrt{\frac{GM}{R}\left( 1+2\sqrt{2} \right)}\]

C)  \[\sqrt{\frac{GM}{R}}\] D)       \[\sqrt{2\sqrt{2}\frac{GM}{R}}\] Correct Answer: B Solution : [b]