question_answer

Two stars of masses \[3\times {{10}^{31}}\] kg each, and at distance \[2\times {{10}^{11}}\] m rotate in a plane about their common centre of mass 0. A meteorite passes through 0 moving perpendicular to the star’s rotation plane. In order to escape from the gravitational field of this double star, the minimum speed that meteorite should have at 0 is-  (Take       Gravitational      constant;           \[G=6.67\times {{10}^{-11}}\,N{{m}^{2}}k{{g}^{-}}^{2})\]            [JEE Main 10-Jan-2019 Evening]

A)  \[2.4\times {{10}^{4}}m/s\]

B)       \[1.4\times {{10}^{5}}m/s\]

C)  \[3.8\times {{10}^{4}}m/s\]

D)       \[2.8\times {{10}^{5}}m/s\]

Correct Answer: D Solution : [d]

When total mechanical energy of meteorite become 0

then meteorite will escape out