| Four identical particles of mass M are located at the corners of a square of side 'a'. What should be their speed if each of them revolves under the influence of other's gravitational field in a circular orbit circumscribing the square? |
| [JEE Main 8-4-2019 Morning] |
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A) \[1.21\sqrt{\frac{GM}{a}}\]
B) \[1.41\sqrt{\frac{GM}{a}}\]
C) \[1.16\sqrt{\frac{GM}{a}}\]
D) \[1.35\sqrt{\frac{GM}{a}}\]
Correct Answer: C
Solution :
| [c] |
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Net force on particle towards centre of circle is  |
This force will act as centripetal force. Distance of particle from centre of circle is |
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