| Currents of a 10 ampere and 2 ampere are passed through two parallel thin wires A and B respectively in opposite directions. Wire A is infinitely long and the length of the wire B is 2 m. [JEE ONLINE 26-05-2012] |
| The force acting on the conductor B, which is situated at 10 cm distance from A will be |
A) \[8\times {{10}^{-5}}N\]
B) \[5\times {{10}^{-5}}N\]
C) \[8\pi \times {{10}^{-7}}N\]
D) \[4\pi \times {{10}^{-7}}N\]
Correct Answer: A
Solution :
| [a] Force acting on conductor B due to conductor A is given by relation\[F=\frac{{{\mu }_{0}}{{I}_{1}}{{I}_{2}}l}{2\pi r}\] |
| \[l\]-length of conductor B r-distance between two conductors |
| \[\therefore \]\[F=\frac{4\pi \times {{10}^{-7}}\times 10\times 2\times 2}{2\times \pi \times 0.1}=8\times {{10}^{-5}}N\] |
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