A) 1%
B) 2%
C) 6%
D) 3%
Correct Answer: C
Solution :
| [c] Given: \[\frac{\Delta I}{I}\times 100=2%;\] |
| \[\frac{\Delta R}{R}\times 100=1%\]and\[\frac{\Delta t}{t}\times 100=1%\] |
| Heat produced, \[H={{I}^{2}}Rt\] |
| Maximum possible error in heat produced, |
| \[=\frac{\Delta H}{H}\times 100\] |
| \[=2\left( \frac{\Delta I}{I}\times 100 \right)+\frac{\Delta R}{R}\times 100+\frac{\Delta t}{t}\times 100\] |
| \[=2\times 2%+1%+1%=6%\] |
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