| Diameter of a steel ball is measured using a Vernier callipers which has divisions of cm on its main scale (MS) and 10 divisions of its vernier scale (VS) match 9 divisions on the main scale. Three such measurements for a ball are given as: [JEE ONLINE 10-04-2015] | ||||||||||||
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A) 0.56 cm
B) 0.53 cm
C) 0.52 cm
D) 0.59 cm
Correct Answer: D
Solution :
| [d] \[\overline{x}=\frac{{{x}_{1}}+{{x}_{2}}+{{x}_{3}}}{3}\] |
| \[=\frac{0.58+0.54+0.56}{3}\] |
| \[\overline{x}=0.56\] so value = 0.56 + error |
| = 0.56 + 0.03 |
| = 0.59 cm |
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