A) \[\sqrt{\frac{Gh}{{{c}^{5}}}}\]
B) \[\sqrt{\frac{h{{c}^{5}}}{G}}\]
C) \[\sqrt{\frac{Gh}{{{c}^{3}}}}\]
D) \[\sqrt{\frac{{{c}^{3}}}{Gh}}\]
Correct Answer: A
Solution :
[a] \[T\,\,=\,\,k{{G}^{a}}{{h}^{b}}{{c}^{c}}\] |
\[[T]={{[{{M}^{-1}}\,{{L}^{3}}{{T}^{-2}}]}^{a}}\,\,{{[M{{L}^{2}}{{T}^{-1}}]}^{b}}\,{{[L{{T}^{-1}}]}^{c}}\] |
\[=\,\,{{M}^{-a+b}}\,L{{\,}^{3a+2b+c}}\,{{T}^{-2a-b-c}}\] |
\[~-a+b=0\] |
\[\Rightarrow \,\,\,a=b~~~~~~~~...\left( 1 \right)\] |
\[3a+2b+c=0~~~~~~...\left( 2 \right)\] |
\[-2a-b-c=1~~~~~~~~~~~...\left( 3 \right)\] |
\[a+b=1\] |
\[a=b\,\text{=}\,\frac{1}{2}\] |
\[C=-2\,\,\times \,\,\frac{1}{2}-\frac{1}{2}-1=-\frac{5}{2}\] |
\[T\,\propto \,\frac{{{G}^{\frac{1}{2}}}{{h}^{\frac{1}{2}}}}{{{C}^{\frac{5}{2}}}}\,=\,\sqrt{\frac{Gh}{{{C}^{5}}}}\] |
Option [a] |
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