A) \[[M]=[{{T}^{-1}}{{C}^{-2}}h]\]
B) \[[M]=[T{{C}^{-2}}h]\]
C) \[[M]=[{{T}^{-1}}{{C}^{-2}}{{h}^{-1}}]\]
D) \[[M]=[{{T}^{-1}}{{C}^{2}}h]\]
Correct Answer: A
Solution :
| [a] \[M\propto {{T}^{x}}{{v}^{y}}{{h}^{z}}\] |
| \[M'{{L}^{0}}{{T}^{0}}={{(T')}^{x}}{{({{L}^{1}}{{T}^{-1}})}^{y}}{{({{M}^{1}}{{L}^{2}}{{T}^{-1}})}^{z}}\] |
| \[{{M}^{1}}{{L}^{0}}{{T}^{0}}={{M}^{z}}{{L}^{y+2z}}+{{T}^{x-y-z}}\] |
| \[z=1\] |
| \[y+2z=0\] \[x-y-z=0\] |
| \[y=-2\] \[x+2-1=0\] |
| \[x=-1\] |
| \[M\Rightarrow {{T}^{-1}}{{C}^{-2}}{{h}^{1}}\] |
You need to login to perform this action.
You will be redirected in
3 sec
