JEE Main & Advanced Physics Mathematical Tools, Units & Dimensions JEE PYQ - Mathematical Tools Units and Dimensions

  • question_answer
    The dimension of stopping potential \[{{V}_{0}}\] in photoelectric effect in units of Planck’s constant ‘h’, speed of light ‘c’ and Gravitational constant ‘G’ and ampere A is : [JEE MAIN Held On 08-01-2020 Morning]

    A) \[{{h}^{1/3}}{{G}^{2/3}}{{c}^{1/3}}{{A}^{1}}\]

    B) \[{{h}^{2/3}}{{c}^{5/3}}{{G}^{1/3}}{{A}^{1}}\]

    C) \[{{h}^{2/3}}{{c}^{1/3}}{{G}^{4/3}}{{A}^{1}}\]

    D) None of these

    Correct Answer: D

    Solution :

    [d] (No option is correct) Bonus
    Stopping potential \[\left( V \right)\propto {{h}^{x}}{{I}^{y}}{{G}^{z}}{{C}^{r}}\]
    Here, h = plank’s constant \[=\left[ M{{L}^{2}}{{T}^{1}} \right]\]
    \[I=current=\left[ A \right]\]
    G = Gravitational constant \[=\left[ {{M}^{1}}{{L}^{3}}{{T}^{2}} \right]\]
    and       c = speed of light \[=\left[ L{{T}^{1}} \right]\]
    \[\therefore \]      and V = potential \[=\left[ M{{L}^{2}}{{T}^{3}}{{A}^{1}} \right]\]
    \[\therefore \left[ M{{L}^{2}}{{T}^{3}}{{A}^{1}} \right]={{\left[ M{{L}^{2}}{{T}^{1}} \right]}^{x}}{{\left[ A \right]}^{y}}{{\left[ {{M}^{1}}{{L}^{3}}{{T}^{2}} \right]}^{z}}\text{ }{{\left[ L{{T}^{1}} \right]}^{r}}\]Comparing dimension of M, L, T, A, we get
    \[y=1,x=0,z=1,r=5\]
    \[\therefore \]


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