• # question_answer A marble block of mass 2 kg lying on ice when given a velocity of 6 m/s is stopped by friction in 10s. Then, the coefficient of friction is [AIEEE 2003] A)       $0.02$ B) $0.03$ C) $0.06$ D) $0.01$

 [c] Let coefficient of friction be $\mu$, then retardation will be $\mu$g. From equation of motion, v = u + at, we get $0=6-\mu g\times 10$                ($\because a=\mu g$) $\Rightarrow$   $\mu =\frac{6}{100}=0.06$