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JEE Main & Advanced Physics NLM, Friction, Circular Motion JEE PYQ - NLM Friction Circular Motion

  • question_answer
    A force\[F=(5\hat{i}+3\hat{j}+2\hat{k})\] is applied over a particle which displaces it from its origin to the point\[r=(2\hat{i}-\hat{j})m\]. The work done on the particle in joules is                     [AIEEE 2004]

    A) - 7

    B) + 7

    C) + 10

    D) + 13

    Correct Answer: B

    Solution :

    [b] Work done in displacing the particle
    \[W=F.r=(5\hat{i}+3\hat{j}+2\hat{k}).(2\hat{i}-\hat{j})\]
    \[=5\times 2+3\times (-1)+2\times 0=10-3=7\,J\]


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