JEE Main & Advanced Physics NLM, Friction, Circular Motion JEE PYQ - NLM Friction Circular Motion

  • question_answer
    The upper half of an inclined plane with inclination\[\phi \]is perfectly smooth, while the lower half is rough. A body starting from rest at the top will again come to rest at the bottom, if the coefficient of friction for the lower half is given by                                         [AIEEE 2005]

    A) \[2\sin \phi \]

    B) \[2\cos \phi \]

    C) \[2\tan \phi \]

    D) \[\tan \phi \]

    Correct Answer: C

    Solution :

    [c] According to work-energy theorem,
    (initial and final speeds are zero)
    Work done by friction + Work done by gravity =0
    \[-\,(\mu \,mg\,cos\phi )\,\frac{l}{2}\,+mgl\,\sin \phi =0\]
    (friction will start at 1/2)
    or


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