JEE Main & Advanced Physics NLM, Friction, Circular Motion JEE PYQ - NLM Friction Circular Motion

  • question_answer
    A player caught a cricket ball of mass 150 g moving at a rate of 20 m/s. If the catching process is completed in 0.1 s, the force of the blow exerted by the ball on the hand of the player is equal to             [AIEEE 2006]

    A) 150N

    B) 3N

    C) 30N

    D) 300N

    Correct Answer: C

    Solution :

    [c] This is the question based on impulse-momentum theorem.
    \[|J|=|F.\Delta t|=|Change\text{ }in\text{ }momentum|\]
    \[\Rightarrow \]   \[F\times 0.1=|{{p}_{f}}-{{p}_{i}}|\]
    As the ball will stop after catching.
    \[\therefore \] \[{{p}_{i}}=m{{v}_{i}}=0.15\times 20=3,\text{ }{{p}_{f}}=0\]
    \[\Rightarrow \] \[F\times 0.1=3\Rightarrow F=30\text{ }N\]


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