JEE Main & Advanced Physics NLM, Friction, Circular Motion JEE PYQ - NLM Friction Circular Motion

  • question_answer
    A block of mass m is connected to another block of mass M by a spring (massless) of spring constant k. The blocks are kept on a smooth horizontal plane. Initially the blocks are at rest and' the spring is upstretched.Then, a constant force F starts acting on the block of mass M to pull it; Find the force on the block of mass m. [AIEEE 2007]

    A) \[c=x\hat{i}+(x-2)\hat{j}-\hat{k}\]

    B) \[x\]

    C) \[R=(3,3\sqrt{3})\]

    D) \[\angle PQR\]

    Correct Answer: C

    Solution :

    [c] Acceleration of system, \[\frac{\sqrt{3}}{2}x+y=0\]
    So, force acting on mass\[x+\sqrt{3}y=0\]

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