• # question_answer For a particle in uniform circular motion, the acceleration$\overrightarrow{a}$at a point$P(R,\text{ }\theta )$on the circle of radius R is (Here$\theta$is measured from the x-axis)                                            [AIEEE 2010] A) $\frac{{{v}^{2}}}{R}\hat{i}+\frac{{{v}^{2}}}{R}\hat{j}$                 B) $-\frac{{{v}^{2}}}{R}\cos \theta \hat{i}+\frac{{{v}^{2}}}{R}\sin \theta \hat{j}$ C) $-\frac{{{v}^{2}}}{R}sin\theta \hat{i}+\frac{{{v}^{2}}}{R}\cos \theta \hat{j}$            D) $-\frac{{{v}^{2}}}{R}\cos \theta \hat{i}-\frac{{{v}^{2}}}{R}sin\theta \hat{j}$

 [d] $\overrightarrow{a}={{a}_{c}}\cos \theta (-\hat{i})+{{a}_{c}}\sin \theta (-\hat{j})$ $\overrightarrow{a}=-\frac{{{V}^{2}}}{R}\cos \theta \hat{i}-\frac{{{V}^{2}}}{R}\sin \theta \hat{j}$