• # question_answer A uniform sphere of weight W and radius 5cm is being held by a string as shown in the figure. The tension in the string will be:                                              [JEE ONLINE 09-04-2013] A)             $12\frac{W}{5}$ B) $5\frac{W}{12}$ C)             $13\frac{W}{12}$ D) $13\frac{W}{12}$

 [d] $T\cos \theta =w$ $T=\frac{w}{\cos \theta }$ $\cos \theta =\frac{AB}{AC}=\frac{AB}{AD+BC}=\frac{AB}{8+5}=\frac{AB}{13}$ From right angle triangle $AB=12$ So                    $T=\frac{w\times 13}{12}$