JEE Main & Advanced Physics NLM, Friction, Circular Motion JEE PYQ - NLM Friction Circular Motion

  • question_answer
    A small ball of mass m starts at a point A with speed \[{{v}_{0}}\] and moves along a frictionless track AB as shown. The track BC has coefficient of friction m. The ball comes to stop at C after travelling a distance L which is:
    [JEE ONLINE 11-04-2014]

    A) \[\frac{2h}{\mu }+\frac{v_{o}^{2}}{2\mu g}\]

    B) \[\frac{h}{\mu }+\frac{v_{o}^{2}}{2\mu g}\]

    C) \[\frac{h}{2\mu }+\frac{v_{o}^{2}}{\mu g}\]

    D) \[\frac{h}{2\mu }+\frac{v_{o}^{2}}{2\mu g}\]

    Correct Answer: B

    Solution :

    [b] Initial speed at point A, \[u={{v}_{0}}\]
    Speed at point B, v = ?
    \[{{v}^{2}}-{{u}^{2}}=2gh\]
    \[{{v}^{2}}=v_{0}^{2}+2gh\]
    Let ball travels distance ‘S’ before coming to rest\[S=\frac{{{v}^{2}}}{2\mu g}=\frac{v_{0}^{2}+2gh}{2\mu g}\]
    \[=\frac{v_{0}^{2}}{2\mu g}=\frac{2gh}{2\mu g}=\frac{h}{\mu }+\frac{v_{0}^{2}}{2\mu g}\]


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