JEE Main & Advanced Physics NLM, Friction, Circular Motion JEE PYQ - NLM Friction Circular Motion

  • question_answer
    Given in the figure are two blocks A and B of weight 20 N and 100N respectively. There are being pressed against a wall by a force F as shown. If the coefficient of friction between the blocks is 0.1 and between block B and the wall is 0.15, the frictional force applied by the wall on block B is:                       [JEE MAIN 2015]

    A) 120 N

    B) 150 N

    C) 100 N

    D) 80 N: D

    Correct Answer: A

    Solution :

    F = 120
    F = 120
    If the system is not acceleration: D

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